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To take the next step — and we’re close to the finish line! — note that the proof doesn’t put any constraint on the upper value of K. If we choose some definite K1, the proof establishes the existence of a single 2-good pair, which we can label a1 and b1. If we choose K2, it proves the existence of a pair we’ll call a2 and b2; that pair may or may not produce a functionally different approximation of r. Maybe there’s just a single solution that repeats for every K?
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这种“重资产”的服务投入，看似是成本支出，实际也为平台赋能产业提供了信用背书：因为背后有了平台兜底，中小商户才敢于接待复杂的国际订单；因为知道遇到困难能获得有效救援，游客也才敢于探索非标的小众目的地。
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